6(3-x)+(-20)=10+3(4x+2

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Solution for 6(3-x)+(-20)=10+3(4x+2 equation: 



6(3-x)+(-20)=10+3(4x+2

We move all terms to the left:

6(3-x)+(-20)-(10+3(4x+2)=0

We add all the numbers together, and all the variables

6(-1x+3)-(10+3(4x+2)+(-20)=0

We multiply parentheses

-6x-(10+3(4x+2)+(-20)+18=0

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