6(3-x)+(-9)=-4+2(3x+1)-x

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Solution for 6(3-x)+(-9)=-4+2(3x+1)-x equation: 



6(3-x)+(-9)=-4+2(3x+1)-x

We move all terms to the left:

6(3-x)+(-9)-(-4+2(3x+1)-x)=0

We add all the numbers together, and all the variables

6(-1x+3)-(-4+2(3x+1)-x)+(-9)=0

We add all the numbers together, and all the variables

6(-1x+3)-(-4+2(3x+1)-x)-9=0

We multiply parentheses

-6x-(-4+2(3x+1)-x)+18-9=0



We calculate terms in parentheses: -(-4+2(3x+1)-x), so:

-4+2(3x+1)-x

determiningTheFunctionDomain
2(3x+1)-x-4

We add all the numbers together, and all the variables

-1x+2(3x+1)-4

We multiply parentheses

-1x+6x+2-4

We add all the numbers together, and all the variables

5x-2

Back to the equation:

-(5x-2)



We add all the numbers together, and all the variables

-6x-(5x-2)+9=0

We get rid of parentheses

-6x-5x+2+9=0

We add all the numbers together, and all the variables

-11x+11=0

We move all terms containing x to the left, all other terms to the right

-11x=-11

x=-11/-11

x=1

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