6(3-x)+2(-2)(4x-2)=14x-6(x-3)+2

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Solution for 6(3-x)+2(-2)(4x-2)=14x-6(x-3)+2 equation: 



6(3-x)+2(-2)(4x-2)=14x-6(x-3)+2

We move all terms to the left:

6(3-x)+2(-2)(4x-2)-(14x-6(x-3)+2)=0

We add all the numbers together, and all the variables

6(-1x+3)+2(-2)(4x-2)-(14x-6(x-3)+2)=0

We multiply parentheses

-6x+2(-2)(4x-2)-(14x-6(x-3)+2)+18=0

We multiply parentheses ..

-6x+2(-8x+4)-(14x-6(x-3)+2)+18=0



We calculate terms in parentheses: -(14x-6(x-3)+2), so:

14x-6(x-3)+2

We multiply parentheses

14x-6x+18+2

We add all the numbers together, and all the variables

8x+20

Back to the equation:

-(8x+20)



We multiply parentheses

-6x-16x-(8x+20)+8+18=0

We get rid of parentheses

-6x-16x-8x-20+8+18=0

We add all the numbers together, and all the variables

-30x+6=0

We move all terms containing x to the left, all other terms to the right

-30x=-6

x=-6/-30

x=1/5

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