6(3-x)+36=98-2(3x+22)

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Solution for 6(3-x)+36=98-2(3x+22) equation: 



6(3-x)+36=98-2(3x+22)

We move all terms to the left:

6(3-x)+36-(98-2(3x+22))=0

We add all the numbers together, and all the variables

6(-1x+3)-(98-2(3x+22))+36=0

We multiply parentheses

-6x-(98-2(3x+22))+18+36=0



We calculate terms in parentheses: -(98-2(3x+22)), so:

98-2(3x+22)

determiningTheFunctionDomain
-2(3x+22)+98

We multiply parentheses

-6x-44+98

We add all the numbers together, and all the variables

-6x+54

Back to the equation:

-(-6x+54)



We add all the numbers together, and all the variables

-6x-(-6x+54)+54=0

We get rid of parentheses

-6x+6x-54+54=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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