6(3-x)-5(2x-4)=4(3x-)+14

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Solution for 6(3-x)-5(2x-4)=4(3x-)+14 equation: 



6(3-x)-5(2x-4)=4(3x-)+14

We move all terms to the left:

6(3-x)-5(2x-4)-(4(3x-)+14)=0

We add all the numbers together, and all the variables

6(-1x+3)-5(2x-4)-(4(+3x)+14)=0

We multiply parentheses

-6x-10x-(4(+3x)+14)+18+20=0



We calculate terms in parentheses: -(4(+3x)+14), so:

4(+3x)+14

We multiply parentheses

12x+14

Back to the equation:

-(12x+14)



We add all the numbers together, and all the variables

-16x-(12x+14)+38=0

We get rid of parentheses

-16x-12x-14+38=0

We add all the numbers together, and all the variables

-28x+24=0

We move all terms containing x to the left, all other terms to the right

-28x=-24

x=-24/-28

x=6/7

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