6(3-z)=2z+4-z

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Solution for 6(3-z)=2z+4-z equation: 



6(3-z)=2z+4-z

We move all terms to the left:

6(3-z)-(2z+4-z)=0

We add all the numbers together, and all the variables

6(-1z+3)-(z+4)=0

We multiply parentheses

-6z-(z+4)+18=0

We get rid of parentheses

-6z-z-4+18=0

We add all the numbers together, and all the variables

-7z+14=0

We move all terms containing z to the left, all other terms to the right

-7z=-14

z=-14/-7

z=+2

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