6(3a+1)-12=3(2a-6)

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Solution for 6(3a+1)-12=3(2a-6) equation: 



6(3a+1)-12=3(2a-6)

We move all terms to the left:

6(3a+1)-12-(3(2a-6))=0

We multiply parentheses

18a-(3(2a-6))+6-12=0



We calculate terms in parentheses: -(3(2a-6)), so:

3(2a-6)

We multiply parentheses

6a-18

Back to the equation:

-(6a-18)



We add all the numbers together, and all the variables

18a-(6a-18)-6=0

We get rid of parentheses

18a-6a+18-6=0

We add all the numbers together, and all the variables

12a+12=0

We move all terms containing a to the left, all other terms to the right

12a=-12

a=-12/12

a=-1

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