6(3a+1)-30=3(2a-40)

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Solution for 6(3a+1)-30=3(2a-40) equation: 



6(3a+1)-30=3(2a-40)

We move all terms to the left:

6(3a+1)-30-(3(2a-40))=0

We multiply parentheses

18a-(3(2a-40))+6-30=0



We calculate terms in parentheses: -(3(2a-40)), so:

3(2a-40)

We multiply parentheses

6a-120

Back to the equation:

-(6a-120)



We add all the numbers together, and all the variables

18a-(6a-120)-24=0

We get rid of parentheses

18a-6a+120-24=0

We add all the numbers together, and all the variables

12a+96=0

We move all terms containing a to the left, all other terms to the right

12a=-96

a=-96/12

a=-8

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