6(3a+1)-30=3(3a-4)

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Solution for 6(3a+1)-30=3(3a-4) equation: 



6(3a+1)-30=3(3a-4)

We move all terms to the left:

6(3a+1)-30-(3(3a-4))=0

We multiply parentheses

18a-(3(3a-4))+6-30=0



We calculate terms in parentheses: -(3(3a-4)), so:

3(3a-4)

We multiply parentheses

9a-12

Back to the equation:

-(9a-12)



We add all the numbers together, and all the variables

18a-(9a-12)-24=0

We get rid of parentheses

18a-9a+12-24=0

We add all the numbers together, and all the variables

9a-12=0

We move all terms containing a to the left, all other terms to the right

9a=12

a=12/9

a=1+1/3

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