6(3a+1)-32=5a-(2a-4)

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Solution for 6(3a+1)-32=5a-(2a-4) equation: 



6(3a+1)-32=5a-(2a-4)

We move all terms to the left:

6(3a+1)-32-(5a-(2a-4))=0

We multiply parentheses

18a-(5a-(2a-4))+6-32=0



We calculate terms in parentheses: -(5a-(2a-4)), so:

5a-(2a-4)

We get rid of parentheses

5a-2a+4

We add all the numbers together, and all the variables

3a+4

Back to the equation:

-(3a+4)



We add all the numbers together, and all the variables

18a-(3a+4)-26=0

We get rid of parentheses

18a-3a-4-26=0

We add all the numbers together, and all the variables

15a-30=0

We move all terms containing a to the left, all other terms to the right

15a=30

a=30/15

a=2

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