6(3a+1)-32=5a-(2a-4)

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Solution for 6(3a+1)-32=5a-(2a-4) equation:



6(3a+1)-32=5a-(2a-4)
We move all terms to the left:
6(3a+1)-32-(5a-(2a-4))=0
We multiply parentheses
18a-(5a-(2a-4))+6-32=0
We calculate terms in parentheses: -(5a-(2a-4)), so:
5a-(2a-4)
We get rid of parentheses
5a-2a+4
We add all the numbers together, and all the variables
3a+4
Back to the equation:
-(3a+4)
We add all the numbers together, and all the variables
18a-(3a+4)-26=0
We get rid of parentheses
18a-3a-4-26=0
We add all the numbers together, and all the variables
15a-30=0
We move all terms containing a to the left, all other terms to the right
15a=30
a=30/15
a=2

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