6(3a+1)-42=1/2(2a-4)

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Solution for 6(3a+1)-42=1/2(2a-4) equation: 



6(3a+1)-42=1/2(2a-4)

We move all terms to the left:

6(3a+1)-42-(1/2(2a-4))=0



Domain of the equation: 2(2a-4))!=0

a∈R



We multiply parentheses

18a-(1/2(2a-4))+6-42=0

We multiply all the terms by the denominator


18a*2(2a-4))-(1+6*2(2a-4))-42*2(2a-4))=0

We add all the numbers together, and all the variables

18a*2(2a-4))-(1+6*2(2a-4))-42*2(2a=0

Wy multiply elements

36a^2(2+24a^2(2=0

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