6(3a+1)=30+3(2a-4)

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Solution for 6(3a+1)=30+3(2a-4) equation: 



6(3a+1)=30+3(2a-4)

We move all terms to the left:

6(3a+1)-(30+3(2a-4))=0

We multiply parentheses

18a-(30+3(2a-4))+6=0



We calculate terms in parentheses: -(30+3(2a-4)), so:

30+3(2a-4)

determiningTheFunctionDomain
3(2a-4)+30

We multiply parentheses

6a-12+30

We add all the numbers together, and all the variables

6a+18

Back to the equation:

-(6a+18)



We get rid of parentheses

18a-6a-18+6=0

We add all the numbers together, and all the variables

12a-12=0

We move all terms containing a to the left, all other terms to the right

12a=12

a=12/12

a=1

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