6(3a+4)=11(a-1)+19

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Solution for 6(3a+4)=11(a-1)+19 equation: 



6(3a+4)=11(a-1)+19

We move all terms to the left:

6(3a+4)-(11(a-1)+19)=0

We multiply parentheses

18a-(11(a-1)+19)+24=0



We calculate terms in parentheses: -(11(a-1)+19), so:

11(a-1)+19

We multiply parentheses

11a-11+19

We add all the numbers together, and all the variables

11a+8

Back to the equation:

-(11a+8)



We get rid of parentheses

18a-11a-8+24=0

We add all the numbers together, and all the variables

7a+16=0

We move all terms containing a to the left, all other terms to the right

7a=-16

a=-16/7

a=-2+2/7

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