6(3a-2)=3(a+5)+3

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Solution for 6(3a-2)=3(a+5)+3 equation: 



6(3a-2)=3(a+5)+3

We move all terms to the left:

6(3a-2)-(3(a+5)+3)=0

We multiply parentheses

18a-(3(a+5)+3)-12=0



We calculate terms in parentheses: -(3(a+5)+3), so:

3(a+5)+3

We multiply parentheses

3a+15+3

We add all the numbers together, and all the variables

3a+18

Back to the equation:

-(3a+18)



We get rid of parentheses

18a-3a-18-12=0

We add all the numbers together, and all the variables

15a-30=0

We move all terms containing a to the left, all other terms to the right

15a=30

a=30/15

a=2

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