6(3a-4)+)3a+4)=5(a-2)-10

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Solution for 6(3a-4)+)3a+4)=5(a-2)-10 equation: 



6(3a-4)+)3a+4)=5(a-2)-10

We move all terms to the left:

6(3a-4)+)3a+4)-(5(a-2)-10)=0

We add all the numbers together, and all the variables

6(3a-4)+)3a+4)-(5(a=0

We multiply parentheses

18a+)3a+4)-(5(a-24=0

We move all terms containing a to the left, all other terms to the right

18a+)3a+4)-(5(a=24

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