6(3b+1)+(19b-3)=0

Solution for 6(3b+1)+(19b-3)=0 equation:

Simplifying
6(3b + 1) + (19b + -3) = 0

Reorder the terms:
6(1 + 3b) + (19b + -3) = 0
(1 * 6 + 3b * 6) + (19b + -3) = 0
(6 + 18b) + (19b + -3) = 0

Reorder the terms:
6 + 18b + (-3 + 19b) = 0

Remove parenthesis around (-3 + 19b)
6 + 18b + -3 + 19b = 0

Reorder the terms:
6 + -3 + 18b + 19b = 0

Combine like terms: 6 + -3 = 3
3 + 18b + 19b = 0

Combine like terms: 18b + 19b = 37b
3 + 37b = 0

Solving
3 + 37b = 0

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + 37b = 0 + -3

Combine like terms: 3 + -3 = 0
0 + 37b = 0 + -3
37b = 0 + -3

Combine like terms: 0 + -3 = -3
37b = -3

Divide each side by '37'.
b = -0.08108108108

Simplifying
b = -0.08108108108