6(3b-4)+(2b-5)=140

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Solution for 6(3b-4)+(2b-5)=140 equation: 



6(3b-4)+(2b-5)=140

We move all terms to the left:

6(3b-4)+(2b-5)-(140)=0

We multiply parentheses

18b+(2b-5)-24-140=0

We get rid of parentheses

18b+2b-5-24-140=0

We add all the numbers together, and all the variables

20b-169=0

We move all terms containing b to the left, all other terms to the right

20b=169

b=169/20

b=8+9/20

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