6(3c+1)-30=3(2c-4)

Solution for 6(3c+1)-30=3(2c-4) equation:

6(3c+1)-30=3(2c-4)

We move all terms to the left:

6(3c+1)-30-(3(2c-4))=0

We multiply parentheses

18c-(3(2c-4))+6-30=0


We calculate terms in parentheses: -(3(2c-4)), so:

3(2c-4)

We multiply parentheses

6c-12

Back to the equation:

-(6c-12)


We add all the numbers together, and all the variables

18c-(6c-12)-24=0

We get rid of parentheses

18c-6c+12-24=0

We add all the numbers together, and all the variables

12c-12=0

We move all terms containing c to the left, all other terms to the right

12c=12

c=12/12

c=1