6(3c-1)-c=-40

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Solution for 6(3c-1)-c=-40 equation: 



6(3c-1)-c=-40

We move all terms to the left:

6(3c-1)-c-(-40)=0

We add all the numbers together, and all the variables

-1c+6(3c-1)+40=0

We multiply parentheses

-1c+18c-6+40=0

We add all the numbers together, and all the variables

17c+34=0

We move all terms containing c to the left, all other terms to the right

17c=-34

c=-34/17

c=-2

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