6(3c-20)=10(c-12)-(-8c)

Solution for 6(3c-20)=10(c-12)-(-8c) equation:

6(3c-20)=10(c-12)-(-8c)

We simplify the equation to the form, which is simple to understand 
6(3c-20)=10(c-12)-(-8c)

Reorder the terms in parentheses
+(+18c-120)=10*(c-12)-(-8c)

Remove unnecessary parentheses
+18c-120=+10+*(+c-12+)-(-8c+)

Reorder the terms in parentheses
+18c-120=+(+10c-120)-(-8c)

Remove unnecessary parentheses
+18c-120=+10c-120-(-8c+)

Remove unnecessary parentheses
+18c-120=+10c-120+8c

We move all terms containing c to the left and all other terms to the right. 
+18c-10c-8c=-120+120

We simplify left and right side of the equation. 
c=0

0=0

This equation is an identity, so all real numbers are solutions.