6(3c-4)=8(7+c)

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Solution for 6(3c-4)=8(7+c) equation: 



6(3c-4)=8(7+c)

We move all terms to the left:

6(3c-4)-(8(7+c))=0

We add all the numbers together, and all the variables

6(3c-4)-(8(c+7))=0

We multiply parentheses

18c-(8(c+7))-24=0



We calculate terms in parentheses: -(8(c+7)), so:

8(c+7)

We multiply parentheses

8c+56

Back to the equation:

-(8c+56)



We get rid of parentheses

18c-8c-56-24=0

We add all the numbers together, and all the variables

10c-80=0

We move all terms containing c to the left, all other terms to the right

10c=80

c=80/10

c=8

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