6(3d-5)=7(3d-2)

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Solution for 6(3d-5)=7(3d-2) equation: 



6(3d-5)=7(3d-2)

We move all terms to the left:

6(3d-5)-(7(3d-2))=0

We multiply parentheses

18d-(7(3d-2))-30=0



We calculate terms in parentheses: -(7(3d-2)), so:

7(3d-2)

We multiply parentheses

21d-14

Back to the equation:

-(21d-14)



We get rid of parentheses

18d-21d+14-30=0

We add all the numbers together, and all the variables

-3d-16=0

We move all terms containing d to the left, all other terms to the right

-3d=16

d=16/-3

d=-5+1/3

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