6(3g-1)=4(2g+5)-6

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Solution for 6(3g-1)=4(2g+5)-6 equation: 



6(3g-1)=4(2g+5)-6

We move all terms to the left:

6(3g-1)-(4(2g+5)-6)=0

We multiply parentheses

18g-(4(2g+5)-6)-6=0



We calculate terms in parentheses: -(4(2g+5)-6), so:

4(2g+5)-6

We multiply parentheses

8g+20-6

We add all the numbers together, and all the variables

8g+14

Back to the equation:

-(8g+14)



We get rid of parentheses

18g-8g-14-6=0

We add all the numbers together, and all the variables

10g-20=0

We move all terms containing g to the left, all other terms to the right

10g=20

g=20/10

g=2

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