6(3k-1)-96=-4(1+k)

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Solution for 6(3k-1)-96=-4(1+k) equation: 



6(3k-1)-96=-4(1+k)

We move all terms to the left:

6(3k-1)-96-(-4(1+k))=0

We add all the numbers together, and all the variables

6(3k-1)-(-4(k+1))-96=0

We multiply parentheses

18k-(-4(k+1))-6-96=0



We calculate terms in parentheses: -(-4(k+1)), so:

-4(k+1)

We multiply parentheses

-4k-4

Back to the equation:

-(-4k-4)



We add all the numbers together, and all the variables

18k-(-4k-4)-102=0

We get rid of parentheses

18k+4k+4-102=0

We add all the numbers together, and all the variables

22k-98=0

We move all terms containing k to the left, all other terms to the right

22k=98

k=98/22

k=4+5/11

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