6(3m+1)=8(2m-5)-4

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Solution for 6(3m+1)=8(2m-5)-4 equation: 



6(3m+1)=8(2m-5)-4

We move all terms to the left:

6(3m+1)-(8(2m-5)-4)=0

We multiply parentheses

18m-(8(2m-5)-4)+6=0



We calculate terms in parentheses: -(8(2m-5)-4), so:

8(2m-5)-4

We multiply parentheses

16m-40-4

We add all the numbers together, and all the variables

16m-44

Back to the equation:

-(16m-44)



We get rid of parentheses

18m-16m+44+6=0

We add all the numbers together, and all the variables

2m+50=0

We move all terms containing m to the left, all other terms to the right

2m=-50

m=-50/2

m=-25

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