6(3n+1)-3=18(n-2)+39

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Solution for 6(3n+1)-3=18(n-2)+39 equation: 



6(3n+1)-3=18(n-2)+39

We move all terms to the left:

6(3n+1)-3-(18(n-2)+39)=0

We multiply parentheses

18n-(18(n-2)+39)+6-3=0



We calculate terms in parentheses: -(18(n-2)+39), so:

18(n-2)+39

We multiply parentheses

18n-36+39

We add all the numbers together, and all the variables

18n+3

Back to the equation:

-(18n+3)



We add all the numbers together, and all the variables

18n-(18n+3)+3=0

We get rid of parentheses

18n-18n-3+3=0

We add all the numbers together, and all the variables

=0

n=0/1

n=0

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