6(3n+1)=7(7n+5)+3

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Solution for 6(3n+1)=7(7n+5)+3 equation: 



6(3n+1)=7(7n+5)+3

We move all terms to the left:

6(3n+1)-(7(7n+5)+3)=0

We multiply parentheses

18n-(7(7n+5)+3)+6=0



We calculate terms in parentheses: -(7(7n+5)+3), so:

7(7n+5)+3

We multiply parentheses

49n+35+3

We add all the numbers together, and all the variables

49n+38

Back to the equation:

-(49n+38)



We get rid of parentheses

18n-49n-38+6=0

We add all the numbers together, and all the variables

-31n-32=0

We move all terms containing n to the left, all other terms to the right

-31n=32

n=32/-31

n=-1+1/31

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