6(3n+1)=7(9n+4)+1

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Solution for 6(3n+1)=7(9n+4)+1 equation: 



6(3n+1)=7(9n+4)+1

We move all terms to the left:

6(3n+1)-(7(9n+4)+1)=0

We multiply parentheses

18n-(7(9n+4)+1)+6=0



We calculate terms in parentheses: -(7(9n+4)+1), so:

7(9n+4)+1

We multiply parentheses

63n+28+1

We add all the numbers together, and all the variables

63n+29

Back to the equation:

-(63n+29)



We get rid of parentheses

18n-63n-29+6=0

We add all the numbers together, and all the variables

-45n-23=0

We move all terms containing n to the left, all other terms to the right

-45n=23

n=23/-45

n=-23/45

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