6(3n+2)=7(5n+3)+7

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Solution for 6(3n+2)=7(5n+3)+7 equation: 



6(3n+2)=7(5n+3)+7

We move all terms to the left:

6(3n+2)-(7(5n+3)+7)=0

We multiply parentheses

18n-(7(5n+3)+7)+12=0



We calculate terms in parentheses: -(7(5n+3)+7), so:

7(5n+3)+7

We multiply parentheses

35n+21+7

We add all the numbers together, and all the variables

35n+28

Back to the equation:

-(35n+28)



We get rid of parentheses

18n-35n-28+12=0

We add all the numbers together, and all the variables

-17n-16=0

We move all terms containing n to the left, all other terms to the right

-17n=16

n=16/-17

n=-16/17

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