6(3n+2)=7(6n+1)+3

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Solution for 6(3n+2)=7(6n+1)+3 equation:



6(3n+2)=7(6n+1)+3
We move all terms to the left:
6(3n+2)-(7(6n+1)+3)=0
We multiply parentheses
18n-(7(6n+1)+3)+12=0
We calculate terms in parentheses: -(7(6n+1)+3), so:
7(6n+1)+3
We multiply parentheses
42n+7+3
We add all the numbers together, and all the variables
42n+10
Back to the equation:
-(42n+10)
We get rid of parentheses
18n-42n-10+12=0
We add all the numbers together, and all the variables
-24n+2=0
We move all terms containing n to the left, all other terms to the right
-24n=-2
n=-2/-24
n=1/12

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