6(3n+2)=7(6n+1)+3

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Solution for 6(3n+2)=7(6n+1)+3 equation: 



6(3n+2)=7(6n+1)+3

We move all terms to the left:

6(3n+2)-(7(6n+1)+3)=0

We multiply parentheses

18n-(7(6n+1)+3)+12=0



We calculate terms in parentheses: -(7(6n+1)+3), so:

7(6n+1)+3

We multiply parentheses

42n+7+3

We add all the numbers together, and all the variables

42n+10

Back to the equation:

-(42n+10)



We get rid of parentheses

18n-42n-10+12=0

We add all the numbers together, and all the variables

-24n+2=0

We move all terms containing n to the left, all other terms to the right

-24n=-2

n=-2/-24

n=1/12

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