6(3n+3)+n=132

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Solution for 6(3n+3)+n=132 equation: 



6(3n+3)+n=132

We move all terms to the left:

6(3n+3)+n-(132)=0

We add all the numbers together, and all the variables

n+6(3n+3)-132=0

We multiply parentheses

n+18n+18-132=0

We add all the numbers together, and all the variables

19n-114=0

We move all terms containing n to the left, all other terms to the right

19n=114

n=114/19

n=6

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