6(3n-1)=(8n+2)+8

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Solution for 6(3n-1)=(8n+2)+8 equation: 



6(3n-1)=(8n+2)+8

We move all terms to the left:

6(3n-1)-((8n+2)+8)=0

We multiply parentheses

18n-((8n+2)+8)-6=0



We calculate terms in parentheses: -((8n+2)+8), so:

(8n+2)+8

We get rid of parentheses

8n+2+8

We add all the numbers together, and all the variables

8n+10

Back to the equation:

-(8n+10)



We get rid of parentheses

18n-8n-10-6=0

We add all the numbers together, and all the variables

10n-16=0

We move all terms containing n to the left, all other terms to the right

10n=16

n=16/10

n=1+3/5

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