6(3n-1)=(n+4)

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Solution for 6(3n-1)=(n+4) equation: 



6(3n-1)=(n+4)

We move all terms to the left:

6(3n-1)-((n+4))=0

We multiply parentheses

18n-((n+4))-6=0



We calculate terms in parentheses: -((n+4)), so:

(n+4)

We get rid of parentheses

n+4

Back to the equation:

-(n+4)



We get rid of parentheses

18n-n-4-6=0

We add all the numbers together, and all the variables

17n-10=0

We move all terms containing n to the left, all other terms to the right

17n=10

n=10/17

n=10/17

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