6(3n-4)=(6n+1)+2

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Solution for 6(3n-4)=(6n+1)+2 equation: 



6(3n-4)=(6n+1)+2

We move all terms to the left:

6(3n-4)-((6n+1)+2)=0

We multiply parentheses

18n-((6n+1)+2)-24=0



We calculate terms in parentheses: -((6n+1)+2), so:

(6n+1)+2

We get rid of parentheses

6n+1+2

We add all the numbers together, and all the variables

6n+3

Back to the equation:

-(6n+3)



We get rid of parentheses

18n-6n-3-24=0

We add all the numbers together, and all the variables

12n-27=0

We move all terms containing n to the left, all other terms to the right

12n=27

n=27/12

n=2+1/4

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