6(3p+1)-30=3(2p-4)

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Solution for 6(3p+1)-30=3(2p-4) equation: 



6(3p+1)-30=3(2p-4)

We move all terms to the left:

6(3p+1)-30-(3(2p-4))=0

We multiply parentheses

18p-(3(2p-4))+6-30=0



We calculate terms in parentheses: -(3(2p-4)), so:

3(2p-4)

We multiply parentheses

6p-12

Back to the equation:

-(6p-12)



We add all the numbers together, and all the variables

18p-(6p-12)-24=0

We get rid of parentheses

18p-6p+12-24=0

We add all the numbers together, and all the variables

12p-12=0

We move all terms containing p to the left, all other terms to the right

12p=12

p=12/12

p=1

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