6(3p+1)-4=9(3p-12)+11

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Solution for 6(3p+1)-4=9(3p-12)+11 equation: 



6(3p+1)-4=9(3p-12)+11

We move all terms to the left:

6(3p+1)-4-(9(3p-12)+11)=0

We multiply parentheses

18p-(9(3p-12)+11)+6-4=0



We calculate terms in parentheses: -(9(3p-12)+11), so:

9(3p-12)+11

We multiply parentheses

27p-108+11

We add all the numbers together, and all the variables

27p-97

Back to the equation:

-(27p-97)



We add all the numbers together, and all the variables

18p-(27p-97)+2=0

We get rid of parentheses

18p-27p+97+2=0

We add all the numbers together, and all the variables

-9p+99=0

We move all terms containing p to the left, all other terms to the right

-9p=-99

p=-99/-9

p=+11

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