6(3q-2)=3(q+5)3

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Solution for 6(3q-2)=3(q+5)3 equation: 



6(3q-2)=3(q+5)3

We move all terms to the left:

6(3q-2)-(3(q+5)3)=0

We multiply parentheses

18q-(3(q+5)3)-12=0



We calculate terms in parentheses: -(3(q+5)3), so:

3(q+5)3

We multiply parentheses

9q+45

Back to the equation:

-(9q+45)



We get rid of parentheses

18q-9q-45-12=0

We add all the numbers together, and all the variables

9q-57=0

We move all terms containing q to the left, all other terms to the right

9q=57

q=57/9

q=6+1/3

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