6(3r-4)=3/8(40r+8)

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Solution for 6(3r-4)=3/8(40r+8) equation: 



6(3r-4)=3/8(40r+8)

We move all terms to the left:

6(3r-4)-(3/8(40r+8))=0



Domain of the equation: 8(40r+8))!=0

r∈R



We multiply parentheses

18r-(3/8(40r+8))-24=0

We multiply all the terms by the denominator


18r*8(40r+8))-(3-24*8(40r+8))=0

Wy multiply elements

144r^2(4-192r(4=0

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