6(3t+2)=2(14t+12)

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Solution for 6(3t+2)=2(14t+12) equation: 



6(3t+2)=2(14t+12)

We move all terms to the left:

6(3t+2)-(2(14t+12))=0

We multiply parentheses

18t-(2(14t+12))+12=0



We calculate terms in parentheses: -(2(14t+12)), so:

2(14t+12)

We multiply parentheses

28t+24

Back to the equation:

-(28t+24)



We get rid of parentheses

18t-28t-24+12=0

We add all the numbers together, and all the variables

-10t-12=0

We move all terms containing t to the left, all other terms to the right

-10t=12

t=12/-10

t=-1+1/5

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