6(3t-1)+13=5(t-2)-3t+4

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Solution for 6(3t-1)+13=5(t-2)-3t+4 equation: 



6(3t-1)+13=5(t-2)-3t+4

We move all terms to the left:

6(3t-1)+13-(5(t-2)-3t+4)=0

We multiply parentheses

18t-(5(t-2)-3t+4)-6+13=0



We calculate terms in parentheses: -(5(t-2)-3t+4), so:

5(t-2)-3t+4

We add all the numbers together, and all the variables

-3t+5(t-2)+4

We multiply parentheses

-3t+5t-10+4

We add all the numbers together, and all the variables

2t-6

Back to the equation:

-(2t-6)



We add all the numbers together, and all the variables

18t-(2t-6)+7=0

We get rid of parentheses

18t-2t+6+7=0

We add all the numbers together, and all the variables

16t+13=0

We move all terms containing t to the left, all other terms to the right

16t=-13

t=-13/16

t=-13/16

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