6(3t-4)+10=5(t-2)-(t-4)

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Solution for 6(3t-4)+10=5(t-2)-(t-4) equation: 



6(3t-4)+10=5(t-2)-(t-4)

We move all terms to the left:

6(3t-4)+10-(5(t-2)-(t-4))=0

We multiply parentheses

18t-(5(t-2)-(t-4))-24+10=0



We calculate terms in parentheses: -(5(t-2)-(t-4)), so:

5(t-2)-(t-4)

We multiply parentheses

5t-(t-4)-10

We get rid of parentheses

5t-t+4-10

We add all the numbers together, and all the variables

4t-6

Back to the equation:

-(4t-6)



We add all the numbers together, and all the variables

18t-(4t-6)-14=0

We get rid of parentheses

18t-4t+6-14=0

We add all the numbers together, and all the variables

14t-8=0

We move all terms containing t to the left, all other terms to the right

14t=8

t=8/14

t=4/7

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