6(3t-4)-4t=5(t-2)

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Solution for 6(3t-4)-4t=5(t-2) equation: 



6(3t-4)-4t=5(t-2)

We move all terms to the left:

6(3t-4)-4t-(5(t-2))=0

We add all the numbers together, and all the variables

-4t+6(3t-4)-(5(t-2))=0

We multiply parentheses

-4t+18t-(5(t-2))-24=0



We calculate terms in parentheses: -(5(t-2)), so:

5(t-2)

We multiply parentheses

5t-10

Back to the equation:

-(5t-10)



We add all the numbers together, and all the variables

14t-(5t-10)-24=0

We get rid of parentheses

14t-5t+10-24=0

We add all the numbers together, and all the variables

9t-14=0

We move all terms containing t to the left, all other terms to the right

9t=14

t=14/9

t=1+5/9

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