6(3v-1)+9v=5(v+2)

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Solution for 6(3v-1)+9v=5(v+2) equation: 



6(3v-1)+9v=5(v+2)

We move all terms to the left:

6(3v-1)+9v-(5(v+2))=0

We add all the numbers together, and all the variables

9v+6(3v-1)-(5(v+2))=0

We multiply parentheses

9v+18v-(5(v+2))-6=0



We calculate terms in parentheses: -(5(v+2)), so:

5(v+2)

We multiply parentheses

5v+10

Back to the equation:

-(5v+10)



We add all the numbers together, and all the variables

27v-(5v+10)-6=0

We get rid of parentheses

27v-5v-10-6=0

We add all the numbers together, and all the variables

22v-16=0

We move all terms containing v to the left, all other terms to the right

22v=16

v=16/22

v=8/11

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