6(3x)+(-20)=10+3(4x+2)

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Solution for 6(3x)+(-20)=10+3(4x+2) equation: 



6(3x)+(-20)=10+3(4x+2)

We move all terms to the left:

6(3x)+(-20)-(10+3(4x+2))=0

We add all the numbers together, and all the variables

63x-(10+3(4x+2))-20=0



We calculate terms in parentheses: -(10+3(4x+2)), so:

10+3(4x+2)

determiningTheFunctionDomain
3(4x+2)+10

We multiply parentheses

12x+6+10

We add all the numbers together, and all the variables

12x+16

Back to the equation:

-(12x+16)



We get rid of parentheses

63x-12x-16-20=0

We add all the numbers together, and all the variables

51x-36=0

We move all terms containing x to the left, all other terms to the right

51x=36

x=36/51

x=12/17

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