6(3x+(6x-4))+14x=32-8x

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Solution for 6(3x+(6x-4))+14x=32-8x equation: 



6(3x+(6x-4))+14x=32-8x

We move all terms to the left:

6(3x+(6x-4))+14x-(32-8x)=0

We add all the numbers together, and all the variables

6(3x+(6x-4))+14x-(-8x+32)=0

We add all the numbers together, and all the variables

14x+6(3x+(6x-4))-(-8x+32)=0

We get rid of parentheses

14x+6(3x+(6x-4))+8x-32=0

We add all the numbers together, and all the variables

22x+6(3x+(6x-4))-32=0

We move all terms containing x to the left, all other terms to the right

22x+6(3x+(6x-4))=32

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