6(3x+1)+1=-3+6x+5(2x+3)

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Solution for 6(3x+1)+1=-3+6x+5(2x+3) equation: 



6(3x+1)+1=-3+6x+5(2x+3)

We move all terms to the left:

6(3x+1)+1-(-3+6x+5(2x+3))=0

We multiply parentheses

18x-(-3+6x+5(2x+3))+6+1=0



We calculate terms in parentheses: -(-3+6x+5(2x+3)), so:

-3+6x+5(2x+3)

determiningTheFunctionDomain
6x+5(2x+3)-3

We multiply parentheses

6x+10x+15-3

We add all the numbers together, and all the variables

16x+12

Back to the equation:

-(16x+12)



We add all the numbers together, and all the variables

18x-(16x+12)+7=0

We get rid of parentheses

18x-16x-12+7=0

We add all the numbers together, and all the variables

2x-5=0

We move all terms containing x to the left, all other terms to the right

2x=5

x=5/2

x=2+1/2

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