6(3x+1)+2(8x-1)=100

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Solution for 6(3x+1)+2(8x-1)=100 equation: 



6(3x+1)+2(8x-1)=100

We move all terms to the left:

6(3x+1)+2(8x-1)-(100)=0

We multiply parentheses

18x+16x+6-2-100=0

We add all the numbers together, and all the variables

34x-96=0

We move all terms containing x to the left, all other terms to the right

34x=96

x=96/34

x=2+14/17

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