6(3x+1)=21(x-1)

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Solution for 6(3x+1)=21(x-1) equation: 



6(3x+1)=21(x-1)

We move all terms to the left:

6(3x+1)-(21(x-1))=0

We multiply parentheses

18x-(21(x-1))+6=0



We calculate terms in parentheses: -(21(x-1)), so:

21(x-1)

We multiply parentheses

21x-21

Back to the equation:

-(21x-21)



We get rid of parentheses

18x-21x+21+6=0

We add all the numbers together, and all the variables

-3x+27=0

We move all terms containing x to the left, all other terms to the right

-3x=-27

x=-27/-3

x=+9

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