6(3x+1)=3(2x+6)

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Solution for 6(3x+1)=3(2x+6) equation: 



6(3x+1)=3(2x+6)

We move all terms to the left:

6(3x+1)-(3(2x+6))=0

We multiply parentheses

18x-(3(2x+6))+6=0



We calculate terms in parentheses: -(3(2x+6)), so:

3(2x+6)

We multiply parentheses

6x+18

Back to the equation:

-(6x+18)



We get rid of parentheses

18x-6x-18+6=0

We add all the numbers together, and all the variables

12x-12=0

We move all terms containing x to the left, all other terms to the right

12x=12

x=12/12

x=1

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