6(3x+1)=6(8x+9)+5

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Solution for 6(3x+1)=6(8x+9)+5 equation:



6(3x+1)=6(8x+9)+5
We move all terms to the left:
6(3x+1)-(6(8x+9)+5)=0
We multiply parentheses
18x-(6(8x+9)+5)+6=0
We calculate terms in parentheses: -(6(8x+9)+5), so:
6(8x+9)+5
We multiply parentheses
48x+54+5
We add all the numbers together, and all the variables
48x+59
Back to the equation:
-(48x+59)
We get rid of parentheses
18x-48x-59+6=0
We add all the numbers together, and all the variables
-30x-53=0
We move all terms containing x to the left, all other terms to the right
-30x=53
x=53/-30
x=-1+23/30

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